При g′(1) g(x)=48 * ⁸√x * ¹²√x

Question

При g′(1) g(x)=48 * ⁸√x * ¹²√x

Answer 1

g'(x) = 48*((1/8)*x^(-7/8)*¹²√x + ⁸√x*(1/12)*x^(-11/12))