1) (1 4/7)^2+2*14/7*33/7+(1 3/7)^2

Question

1) (1 4/7)^2+2*14/7*33/7+(1 3/7)^2

Comments

1 и 4/7 , 14/7, 33/7, 1и3/7?

Answer 1

(1 4/7)² + 2 · 14/7 · 33/7 + (1 3/7)² = 23 целых 18/49

1) (1 4/7)² = 11/7 · 11/7 = 121/49 = 2 23/49

2) 2 · 14/7 = 28/7 = 4

3) 4 · 33/7 = 132/7 = 18 6/7

4) (1 3/7)² = 10/7 · 10/7 = 100/49 = 2 2/49

5) 2 23/49 + 18 6/7 = 2 23/49 + 18 42/49 = 20 65/49 = 21 16/49

6) 21 16/49 + 2 2/49 = 23 18/49