Упростить выражение С решением
(X^1/2y^2/3z^2)^1/2
----------------------------- = [(x^(1/2-2)y^(2/3+1/2)z^(2-1/3) ]^1/2 =
(x^2y^(-1/2)z^1/3)^1/2
=[x^(-3/2) y^(7/2) z^(5/3)]^1/2= x^(-6/2) y^(14/6) z^(10/3) =
=x^(-3)y^(7/2) z^(10/3)
((x^1/2 · y^2/3 · z²) : (x² · y^(-1/2) · z^1/3))^1/2 =
= (x^(-3/2) · y^7/6 · z^5/3)^1/2 =
= x^(-3/4) · y^7/12 · z^5/6