3^х^2>9^8 помогите пожалуйста
9^8\\3^{x^2}>3^{2*8}\\x^2>16\\\left[\begin{array}{ccc}x<-4\\x>4\\\end{array}" alt="3^{x^2}>9^8\\3^{x^2}>3^{2*8}\\x^2>16\\\left[\begin{array}{ccc}x<-4\\x>4\\\end{array}" align="absmiddle" class="latex-formula">
Ответ: x∈(-∞;-4)∪(4;+∞)
9^8\\3^{x^2}>3^{2*8}\\x^2>16\\\left[\begin{array}{ccc}x<-4\\x>4\\\end{array}" alt="3^{x^2}>9^8\\3^{x^2}>3^{2*8}\\x^2>16\\\left[\begin{array}{ccc}x<-4\\x>4\\\end{array}" align="absmiddle" class="latex-formula">