X²-2x+1/x³-x²-x+1 x=1 ⅔

Question

X²-2x+1/x³-x²-x+1 x=1 ⅔

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Задание?

Answer 1

\frac{3}{8}" alt="\frac{x^2-2x+1}{x^3-x^2-x+1}=\frac{(x-1)^2}{x^2(x-1)-(x-1)} =\frac{x-1}{(x-1)(x+1)}=\frac{1}{x+1}=>\frac{3}{8}" align="absmiddle" class="latex-formula">