1) y' = (x² +8x -8)'* e^(x +10) + (x² +8x -8) * (e^(x +10))'=
=(2x+8)*e^(x +10) + (x² +8x -8) * e^(x +10)= e^(x+10)* (2x+8+x² +8x-8)=
=e^(x+10)*(x²+10x)
2) e^(x+10)*(x²+10x), ⇒e^(x+10) ≠ 0, ⇒ (x²+10x)= 0,⇒ x = 0; х = -10
3)0∉ [-14; -6], -10∈[-14; -6]
4) x = -14
= (196 - 112 -8)* e^(-14+10) = 76*e^-4= 76/е⁴
x = -6
y=(36 -48-8)*e^(-6+10) = -20*e⁴
x = -10
y = (100-80-8)*e⁰ = 12
5) Ответ: max y = 12
[-14; -6]