(186²+186*34+34²)+186*34Помогите пж
186^2+186*34+34^2+186*34=186^2+2*186*34+34^2=(186+34)^2= 220^2=48400
(a^2+2ab+b^2)=(a+b)^2 - квадрат суммы.
186^2+186*34+34^2+186*34=
186^2+2*186*34+34^2=
(186+34)^2= 220^2=48400
(186²+186·34+34²)+186·34 =
= 186²+186·34+34²+186·34 =
= 186²+ 2 ·186 ·34+34² =
= (186 + 34)² =
= 220² =
= 48400