Решите. Заранее спасибо!!!!!!!

Решите задачу:

$1) \\ {3}^{7} \times {3}^{ - 6} = \frac{ {3}^{7} }{ {3}^{6} } = 3 \\ {7}^{ - 9} \times {7}^{8} = \frac{ {7}^{8} }{ {7}^{9} } = \frac{1}{7}$

$2) \\ {2}^{5} \div {2}^{6} = {2}^{ - 1} = \frac{1}{2} \\ 5 \div {5}^{ - 2} = {5}^{1 - ( - 2)} = {5}^{3} = 125$

$3) \\ {( {3}^{2}) }^{ - 1} = {3}^{ - 2} = \frac{1}{ {3}^{2} } = \frac{1}{9} \\ {( ({ \frac{1}{2}) }^{ - 3} )}^{ - 2} = {( \frac{1}{2} })^{6} = \frac{1}{64}$

$4) \\ - 17 \times {34}^{ - 1} = - \frac{17}{34} = - \frac{ 1}{2} \\ - 10 \times {2}^{ - 3} = - \frac{10}{ {2}^{3} } = - \frac{10}{8} = - 1 \frac{1}{4} = - 1.25$

$5) \\ 32 \times {2}^{ - 6} = \frac{32}{ {2}^{6} } = \frac{32}{64} = \frac{1}{2} = 0.5 \\ 27 \times ( { {3}^{ - 2}) }^{2} = 27 \times {3}^{ - 4} = \frac{ {3}^{3} }{ {3}^{4} } = \frac{1}{3}$

$6) \\ {81}^{ - 2} \times {27}^{2} = \frac{ {27}^{2} }{ {81}^{2} } = \frac{ {3}^{3} }{ {3}^{4} } = \frac{1}{3} \\ {16}^{ - 5} \div {8}^{ - 6} = \frac{1}{ {16}^{5} } \div \frac{1}{ {8}^{6} } = \frac{ {8}^{6} }{ {16}^{5} } = \frac{( {2}^{3} ) ^{6} }{( { {2}^{4} )}^{5} } = \frac{ {2}^{18} }{ {2}^{20} } = {2}^{ - 2} = \frac{1}{4} = 0.25$