Вообщем, решить то что я кинул)

в)

$3 \frac{1}{8} \div (x - 4 \frac{7}{24} ) = 2 \frac{7}{9} \\ \frac{17}{18} + 1 \frac{5}{6} = 1 \frac{32}{18} = 2 \frac{14}{18} = 2 \frac{7}{9}$

$x - 4 \frac{7}{24} = 3 \frac{1}{8} \div 2 \frac{7}{9} = \frac{25}{8} \div \frac{25}{9} \\ = \frac{25}{8} \times \frac{9}{25} = \frac{9}{8} = 1 \frac{1}{8}$

$x = 1 \frac{1}{8} + 4 \frac{7}{24} = 1 \frac{3}{24} + 4 \frac{7}{24} = \\ 5 \frac{10}{24} = 5 \frac{5}{12}$

$a) \frac{14}{15} \times \frac{45}{84} = \frac{3}{6} + \frac{2}{5} = \frac{15}{30} + \frac{12}{30} = \\ = \frac{27}{30} = \frac{9}{10} = 0.9$

Б)

$\frac{3}{4} \times \frac{8}{9} = \frac{2}{3} \\ 3 \frac{1}{18} - \frac{2}{3} = 3 \frac{1}{18} - \frac{12}{18} =$

$2 \frac{19}{18} - \frac{12}{18} = 2 \frac{7}{18}$

В)

$\frac{2}{7} \times \frac{7}{3} = \frac{2}{3} \div 4 = \frac{2}{3} \times \frac{1}{4} = \frac{1}{6}$

Г)

$1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3} \\ \frac{1}{3} - \frac{1}{4} = \frac{4}{12} - \frac{3}{12} = \frac{1}{12}$

$\frac{2}{3} \div \frac{1}{12} = \frac{2}{3} \times \frac{12}{1} = 8$