Очень срочно решите пожалуйста...

1. $f(x)= sin^{2}x, x= \frac{ \pi }{4} \\ f'(x)= cos x*2sinx=sin(2x) \\ f'( \frac{ \pi }{4})=sin ( \frac{ 2\pi }{4} ) \\ f'( \frac{ \pi }{4})=sin ( \frac{ \pi }{2} ) = 1$

2. $F(x)=ln (cosx), x=- \frac{ \pi }{3} \\ F'(x)= \frac{-sin x}{cos x} =-tg x \\ F'(- \frac{ \pi }{3} )=-tg (- \frac{ \pi }{3}) = \sqrt{3}$

3. $f(t)=sin t -cos^2t, t=0 \\ f'(t)=cost+2cost*sint \\ f'(t)=cost(1+2sint) \\ f'(0)=1(1+2*0)=1$

4. $f(z)=ln(tgz), z= \frac{ \pi }{4} \\ f'(z)= \frac{1}{tgz*cos^2z}= \frac{1}{sinz*cosz} = \frac{2}{2sinz*cosz}= \frac{2}{sin2z} \\ f'( \frac{ \pi }{4} )= \frac{2}{sin \frac{ \pi }{2} } = \frac{2}{1} =2$

5. $f(x)= e^{sinx} , x=0 \\ f'(x)=cosx*e^{sinx} \\ f'(0)=cos0*e^{sin0}=1*e^0=1*1=1$