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Решите задачу:

$3\frac{1}{7} \times \frac{3}{11} + \frac{3}{8} \div \frac{7}{12} = \frac{22}{7} \times \frac{3}{11} + \frac{3}{8} \times \frac{12}{7} = \frac{6}{7} + \frac{9}{14} = \frac{12 + 9}{14} = \frac{21}{14} = \frac{3}{2} = 1.5$

$4 \frac{1}{12} - 3 \frac{7}{8} + 3 \frac{11}{18} \div \frac{13}{18} = \frac{49}{12} - \frac{31}{8} + \frac{65}{18} \times \frac{18}{13} = \frac{98 - 93}{24} + 5 = 5 \frac{5}{24}$

$4 \frac{1}{6} + (2 \frac{3}{4} - 2 \frac{1}{6} ) \div 2 \frac{4}{5} - 1 \frac{3}{8} = \frac{25}{6} + ( \frac{11}{4} - \frac{13}{6}) \div \frac{14}{5} - \frac{11}{8} = \frac{25}{6} + \frac{33 - 26}{12} \div \frac{14}{5} - \frac{11}{8} = \frac{25}{6} + \frac{7}{12} \times \frac{5}{14} - \frac{11}{8} = \frac{25}{6} + \frac{5}{24} - \frac{11}{8} = \frac{100 + 5 - 33}{24} = \frac{72}{24} = 3$

$(2 \frac{1}{2} - \frac{3}{5} \times 2 \frac{1}{2} ) \div \frac{7}{10} + 1 \frac{5}{6} = ( \frac{5}{2} - \frac{3}{5} \times \frac{5}{2}) \div \frac{7}{10} + \frac{11}{6} = ( \frac{5}{2} - \frac{3}{2} ) \div \frac{7}{10} + \frac{11}{6} = \frac{2}{2} \times \frac{10}{7} + \frac{11}{6} = \frac{60 + 77}{42} = \frac{137}{42} = 3 \frac{11}{42}$