\frac{3y+5}4-\frac{3y}2\\\frac{20+7y-3}5>\frac{3y+5-6y}4\\4\cdot(7y+17)>5\cdot(5-3y)\\28y+68>25-15y\\28y+15y>25-68\\43y>-43\\y>-1\\k=1,\;b=-1" alt="4+\frac{7y-3}5>\frac{3y+5}4-\frac{3y}2\\\frac{20+7y-3}5>\frac{3y+5-6y}4\\4\cdot(7y+17)>5\cdot(5-3y)\\28y+68>25-15y\\28y+15y>25-68\\43y>-43\\y>-1\\k=1,\;b=-1" align="absmiddle" class="latex-formula">