(4a^2+2b+b^2)*(2a+b)*(b^2-4a^2)/4a^2+4ab+b^2

Question

(4a^2+2b+b^2)*(2a+b)*(b^2-4a^2)/4a^2+4ab+b^2

Answer 1

(4a^2+2b+b^2)*(2a+b)*(b^2-4a^2)/(4a^2+4ab+b^2)=

=(4a^2+2b+b^2)*(2a+b)*(b-2a)(b+2a)/(2a+b)^2=

=(4a^2+2b+b^2)*(b+2a)*(b-2a)(b+2a)/(b+2a)^2=

=(4a^2+2b+b^2)*(b-2a)

Answer 2

В задании всё верно?????????!!!!!!!!!!

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