Найдём n:
sin\beta_1=0,56;\beta_1=arcsin(0,56)\approx34^{\circ}" alt="\frac{sin\alpha}{sin\beta}=n;\\\\\frac{sin35^{\circ}}{sin25^{\circ}}=n\\\\n\approx1,36\\\\\\\frac{sin\alpha_1}{sin\beta_1}=1,36\\\\\frac{sin50^{\circ}}{sin\beta_1}=1,36\\\\sin\beta_1=\frac{sin50^{\circ}}{n}=>sin\beta_1=0,56;\beta_1=arcsin(0,56)\approx34^{\circ}" align="absmiddle" class="latex-formula">