(x-1)(x^2-4x+4)=6(x-2)
(x - 1)(x² - 4x + 4) = 6(x - 2)
(x - 1)(x - 2)² - 6(x - 2) = 0
(x - 2)(x² - 2x - x + 2 - 6) = 0
(x - 2)(x² - 3x - 4) = 0
(x - 2)(x + 1)(x - 4) = 0
или x - 2 = 0 или x + 1 = 0 или x - 4 = 0
x₁ = 2 x₂ = - 1 x₃ = 4
Ответ : - 1 ; 2 ; 4