Решите задачу:
x-2y+2=0 x=2y-2=2*(y-1)
x²+(y-1)²=5 ⇒
(2*(y-1))²+(y-1)²=
4*(y-1)²+(y=1)²=5
5*(y-1)²=5 |÷5
(y-1)²=1
(y-1)²-1²=0
(y-1+1)*(y-1-1)=0
y*(y-2)=0
y₁=0 ⇒ x-2*0+2=0 x+2=0 x₁=-2
y₂=2 ⇒ x-2*2+2=0 x-4+2=0 x-2=0 x₂=2
Ответ: x₁=-2 y₁=0 x₂=2 y₂=2.