(6 5/9+3 2/7) + (2 7/9+5 2/9- 4 1/3) = ???

$(6\frac{5}{9} + 3\frac{2}{7})+(2\frac{7}{9}+5\frac{2}{9} - 4 \frac{1}{3}) =13 \frac{32}{63}\\\\1) 6\frac{5}{9} + 3\frac{2}{7} = 6\frac{35}{63} + 3 \frac{18}{63} = 9 \frac{53}{63}\\\\2) 2\frac{7}{9} + 5 \frac{2}{9} = 8\\\\3) 8 - 4\frac{1}{3} = 3\frac{2}{3}\\\\4) 9 \frac{53}{63} + 3 \frac{2}{3} = 9 \frac{53}{63} + 3 \frac{42}{63} = 12\frac{95}{63} = 13 \frac{32}{63}$

Ответ: $13 \frac{32}{63}$