Найдите координаты точки пересечения плоскости 2x-y+z-3=0 и прямой, проходящей через...

\\ 4t = x + 1 = > x = 4t - 1 \\t = y \\ z - 2 = 0 \\ z = 2 \\ " alt=" \frac{x + 1}{4} = \frac{y}{1 } = \frac{z - 2}{0} = t \\ = > \\ 4t = x + 1 = > x = 4t - 1 \\t = y \\ z - 2 = 0 \\ z = 2 \\ " align="absmiddle" class="latex-formula">

$2(4t - 1 ) - t + 2 - 3 = 0 \\ 8t - 2 - t + 2 - 3 = 0 \\ 7t = 3 \\ t = \frac{3}{7}$

$x = 4 \times \frac{3}{7} - 1 = \frac{12}{7} - \frac{7}{7} = \frac{5}{7} \\ y = \frac{3}{7} \\ z = 2$