Реши уравнение х²=2х+8
X1=-2 X2=4
х² = 2х + 8
х² - 2х - 8 = 0
D = (-2)² - 4 × 1 × (-8) = 4 + 32 = 36
x1 = ( 2 + 6 ) / 2 = 4
x2 = ( 2 - 6 ) / 2 = -2
Ответ : х1 = 4 ; х2 = -2
x^2-2x-8=0
x^2+2x-4x-8=0
x(x+2)-4(x+2)=0
(x-4)(x+2)=0
x-4=0, x+2=0
x=4, x=-2