-(8x-1)^2\\\\24x-64x^2+9-24x>-(64x^2-16x+1)\\\\24x-64x^2+9-24x>-64x^2+16x-1\\\\-16x>-1-9\\\\-16x>-10|:(-16)\\\\x<\frac{5}{8} " alt="(8x+3)(3-8x)>-(8x-1)^2\\\\24x-64x^2+9-24x>-(64x^2-16x+1)\\\\24x-64x^2+9-24x>-64x^2+16x-1\\\\-16x>-1-9\\\\-16x>-10|:(-16)\\\\x<\frac{5}{8} " align="absmiddle" class="latex-formula">
x∈(-∞:5/8)
Ответ:0