Решите способом подстановки

$\left \{ {{3x-2y=6} \atop {3x+10y=-12}} \right. \\\\\left \{ {{2y=3x-6} \atop {3x+10y=-12}} \right.\\\\\left \{ {{y=1,5x-3} \atop {3x+10(1,5x-3)=-12}} \right.\\\\\left \{ {{y=1,5x-3} \atop {3x+15x-30=-12}} \right.\\\\\left \{ {{y=1,5x-3} \atop {18x=18}} \right.\\\\\left \{ {{x=1} \atop {y=1,5*1-3}} \right.\\\\\left \{ {{x=1} \atop {y=-1,5}} \right.$

Ответ : (1 ; - 1,5)

Решите способом подстановки​

Решите способом подстановки