Как решить 8 7/12+(5 3/40-4 8/15)

$8 \frac{7}{12} + (5 \frac{3}{40 } - 4 \frac{8}{15} )$

По действиям:

$5 \frac{3}{40} - 4 \frac{8}{15} = \frac{203}{40} - \frac{68}{15} = \frac{609}{120} - \frac{544}{120} = \frac{65}{120} = \frac{13}{24}$

$8 \frac{7}{12} + \frac{13}{24} = \frac{8 \times 12 + 7}{12} + \frac{13}{24} = \frac{103}{12} + \frac{13}{24} = \frac{103 \times 2}{12 \times 2} + \frac{13}{24} = \frac{206}{24} + \frac{13}{24} = \frac{219}{24} = 9 \frac{1}{8}$

Ответ: 9 1/8