A 7-3*(x-1)=2x b (x+4)²=x*(x+3)

$a)7 - 3 \times (x - 1) = 2x \\ \\ 7 - 3x + 3 = 2x \\ \\ - 3x - 2x = - 10 \\ \\ - 5x = - 10 \\ \\ x = - 10 \div ( - 5) \\ \\ x = 2 \\ \\ \\ \\ \\ b)(x + 4) {}^{2} = x \times (x + 3) \\ \\ x {}^{2} + 8x + 16 = x {}^{2} + 3x \\ \\ x {}^{2} + 8x + 16 - x {}^{2} - 3x = 0 \\ \\ 8x - 3x = - 16 \\ \\ 5x = - 16 \\ \\ x = - \frac{16}{5} \\ \\ x = - 3 \frac{1}{5}$

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