x=2} \atop {3y-5x=2}} \right.\\3y-10=2;y=12/3=4" alt="\left \{ {{\frac{x+y}{3}-1=\frac{2y-x}{6}|*6} \atop {\frac{y-x}{2}=\frac{y+6}{5}-1|*10}} \right.\\\left \{ {2x+2y-6=2y-x} \atop {5y-5x=2y+12-10}} \right.\\\left \{ {3x=6=>x=2} \atop {3y-5x=2}} \right.\\3y-10=2;y=12/3=4" align="absmiddle" class="latex-formula">
Ответ: (2;4)