Сократите дробь: (a-b)^3/b^2-a^2 x^2-2x+1/x^2-1 5m^2+10mn+5n^2/15m^2-15n^2...

Решите задачу:

$\frac{ {(a - b)}^{3} }{ {b}^{2} - {a}^{2} } = - \frac{ {(a - b)}^{3} }{(a - b)(a + b)} = \frac{ {(a - b)}^{2} }{(a + b)} \\$

$\frac{ {x}^{2} - 2x + 1}{ {x}^{2} - 1} = \frac{ {(x - 1)}^{2} }{(x - 1)(x + 1)} = \frac{x - 1}{x + 1} \\$

$\frac{5 {m}^{2} + 10mn + 5 {n}^{2} }{15 {m}^{2} - 15 {n}^{2} } = \frac{5( {m}^{2} + 2mn + {n}^{2}) }{15( {m}^{2} - {n}^{2} )} = \frac{ {(m + n)}^{2} }{3(m - n)(m + n)} = \frac{(m + n)}{3(m - n)} \\$

$\frac{ {m}^{3} - {m}^{3} }{ {m}^{2} - {n}^{2} } = \frac{0}{{m}^{2} - {n}^{2}} = 0 \\ - - - - - - \\ \frac{ {m}^{3} - {n}^{3} }{ {m}^{2} - {n}^{2} } = \frac{(m - n)( {m}^{2} + mn + {n}^{2} )}{(m - n)(m + n)} = \frac{{m}^{2} + mn + {n}^{2} }{m + n} \\$

$\frac{3 {p}^{2} - 3 {q}^{3} }{6 {p}^{3} - 6 {q}^{3} } = \frac{3( {p}^{2} - {q}^{3}) }{6( {p}^{?} - {q}^{3} ) } = \frac{{p}^{2} - {q}^{3}}{2( {p}^{?} - {q}^{3} ) } \\$