x\\x\in [-11;-5)" alt="\sf\displaystyle \frac{x-1}{x+5}\geq 2\\OD3:x\ne -5\\ \frac{x-1}{x+5}-\frac{2(x+5)}{x+5}\geq 0\\\\ \frac{x-1-2x-10}{x+5} \geq 0\\\\ \frac{-x-11}{x+5}\geq 0|\cdot (-1)\\\\ \frac{x+11}{x+5}\leq 0\\nuli: x=-11;x\ne -5\\ +++[-11]---(-5)+++>x\\x\in [-11;-5)" align="absmiddle" class="latex-formula">
Ответ: 
3\\OD3:x\ne -3\\ \frac{x-1}{x+3}-\frac{3(x+3)}{x+3}>0\\\\ \frac{x-1-3x-9}{x+3} >0\\\\ \frac{-2x-10}{x+3}>0|:(-2)\\\\ \frac{x+5}{x+3}<0\\nuli: x=-5; x\ne -3\\+++[-5]---(-3)+++>x\\ x\in [-5;-3)" alt="\sf\displaystyle \frac{x-1}{x+3}>3\\OD3:x\ne -3\\ \frac{x-1}{x+3}-\frac{3(x+3)}{x+3}>0\\\\ \frac{x-1-3x-9}{x+3} >0\\\\ \frac{-2x-10}{x+3}>0|:(-2)\\\\ \frac{x+5}{x+3}<0\\nuli: x=-5; x\ne -3\\+++[-5]---(-3)+++>x\\ x\in [-5;-3)" align="absmiddle" class="latex-formula">
Ответ: 