Объяснение:
1) y'=10x+6
2) y'=(x^3+1)/2√x+√x*3x^2=(7x^3+1)/2√x
3) (3x^2(x^3+1)-x^3*3x^2)/(x^3+1)^2=(3x^5+3x^2-3x^5)/(x^3+1)^2=
=3x^2/(x^3+1)^2
4) y'=cosx+3x^2
5) y'=6*(7x-9)^5*7=42*(7x-9)^5
6) y'=4/2√(4x+1)=2/√(4x+1)
7) y'=cos(2x-П/3)*2=2*cos(2x-П/3)
2] f'(x)=3x^2+4x-7
f'(x)=0
x=(-2+-5)/3
x1=-7/3
x2=1