СРОЧНО !!!!!! ПОМОГИТЕ !!!!!!!!!

1) x³ - 27y³ + 3x²y - 9xy² = (x³ - 27y³) + (3x²y - 9xy²) =

= (x - 3y)(x² + 3xy + 9y²) + 3xy(x - 3y) = (x - 3y)(x² + 3xy + 9y² + 3xy) =

= (x - 3y)(x² + 6xy + 9y²) = (x - 3y)(x + 3y)²

$2)\left \{ {{\frac{x-2}{4}+\frac{y-2}{4}=2} \atop {\frac{x-2}{3}-\frac{y-2}{9}=\frac{4}{3} }} \right.\\\\\left \{ {{\frac{x-2}{4}*4+\frac{y-2}{4}*4}=2*4 \atop {\frac{x-2}{3}*9-\frac{y-2}{9}*9=\frac{4}{3}*9}} \right.\\\\\left \{ {{x-2+y-2=8} \atop {3x-6-y+2=12}} \right.\\\\+\left \{ {{x+y=12} \atop {3x-y=16}} \right. \\-------\\4x=28\\x=7\\y=12-x=12-7=5$

Ответ : (7 ; 5)