Помогите сделать три номера по алгебре, даю 54 балла. Спасибо

#1.

▪а)

$16 \times {( - 8)}^{ - 1} = 16 \times ( - \frac{1}{8} ) = - 2$

▪б)

${2}^{ - 3} - {( - 2)}^{ - 4} = \frac{1}{8} - \frac{1}{16} = \frac{2 - 1}{16} = \frac{1}{16}$

▪в)

$- {3}^{0} \times {( \frac{2}{3}) }^{ - 1} + {(0.5)}^{ - 2} = - 1 \times \frac{3}{2} + 4 = - 1.5 + 4 = 2.5$

▪г)

${( \frac{1}{5} - \frac{1}{25}) }^{ - 1} \div {(3.2)}^{ - 2} = {( \frac{5 - 1}{25}) }^{ - 1} \div {( \frac{32}{10}) }^{ - 2} = \frac{25}{4} \div {( \frac{16}{5}) }^{ - 2} = \frac{25}{4} \div \frac{25}{ {4}^{4} } = \frac{25 \times {4}^{4} }{4 \times 25} = {4}^{3} = 64$

#3.

▪а)

${a}^{ - 1} {b}^{ - 2} - {a}^{ - 2} {b}^{ - 1} = \frac{1}{a {b}^{2} } - \frac{1}{ {a}^{2} b} = \frac{a - b}{ {a}^{2} {b}^{2} }$

▪б)

$( {xy}^{ - 1} - {x}^{ - 1} y) {(x - y)}^{ - 1} = ( \frac{x}{y} - \frac{y}{x} ) \times \frac{1}{x - y} = \frac{ {x}^{2} - {y}^{2} }{xy} \times \frac{1}{x - y} = \frac{(x - y)(x + y)}{xy(x - y)} = \frac{x + y}{xy}$