Ответ:
Объяснение:
\left \{ {{2^x-1>\frac{1}{8} } \atop {2^x-1\leq16 }} \right. =>\left \{ {{2^x>\frac{9}{8} } \atop {2^x\leq 17 }} \right. =>2log_2(3)-3\left \{ {{2^x-1>\frac{1}{8} } \atop {2^x-1\leq16 }} \right. =>\left \{ {{2^x>\frac{9}{8} } \atop {2^x\leq 17 }} \right. =>2log_2(3)-3