Нужно срочно please))))

Решите задачу:

$1)3^{\frac{1-x}{x-2} }=\frac{1}{9}\\\\3^{\frac{1-x}{x-2} }=3^{-2}\\\\\frac{1-x}{x-2}=-2\\\\\left \{ {{1-x=-2x+4} \atop {x\neq2 }} \right.\\\\-x+2x=4-1\\\\x=3$

$2)(\frac{2}{5})^{3x-7}=(\frac{5}{2})^{7x-3}\\\\(\frac{2}{5})^{3x-7}=(\frac{2}{5} )^{-7x+3}\\\\3x-7=-7x+3\\\\3x+7x=3+7\\\\10x=10\\\\x=1$

$3)(\frac{3}{4})^{x+3}=(\frac{4}{3})^{4-2x}\\\\(\frac{3}{4})^{x+3}=(\frac{3}{4})^{-4+2x}\\\\x+3=-4+2x\\\\x-2x=-4-3\\\\-x=-7\\\\x=7$