Ответ:
дано
m(ppa NaOH) = 200 g
W(NaOH) = 8%
----------------------
V(SO2)-?
m(NaOH) = m(ppa NaOH) * W(NaOH) / 100% = 200 * 8% / 100% = 16 g
2NaOH+SO2-->Na2SO3+H2O
M(NaOH) = 40 g/mol
n(NaOH) = m(NaOH) / M(NaOH) = 16 / 40 = 0.15 mol
2n(NaOH) = n(SO2)
n(SO2) = 0.15 / 2 = 0.075 mol
V(SO2) = n(SO2) * Vm = 0.075 * 22.4 = 1.68 L
ответ 1.68 л
Объяснение: