Ответ:
7) y' = 1/(2*sin(1-2*x)^(1/2))*(-2)*cos(1-2*x)
8) y' = 3 * (-1) * (5x^3 + 4*x)^(-2) * (15*x^2 + 4)
9) y' = (3*x^2 * sin(x) - cos(x) * x^3) / sin(x)^2
Пошаговое объяснение:
7) y = (sin(1-2*x)^(1/2)
y' = 1/(2*sin(1-2*x)^(1/2))*(-2)*cos(1-2*x)
8) y = 3/(5*x^3 + 4*x) = 3 * (5*x^3 + 4*x)^(-1)
y' = 3 * (-1) * (5x^3 + 4*x)^(-2) * (15*x^2 + 4)
9) y = x^3/sin(x)
y' = (3*x^2 * sin(x) - cos(x) * x^3) / sin(x)^2