5х-2(х-4)≤ 5(х+1)
(х-6)(х+6)≤ (х-5)²+9
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5х-2х+8 ≤ 5х+ 5
х²- 36 ≤ х²-10х+25+9
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3х+8 ≤ 5х+5
х²- 36 ≤ х²-10х+34
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8-5 ≤ 5х-3х
х²-х²+10х ≤34+36
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2х ≥ 3
10х≤ 70
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х ≥ 1,5
х ≤ 7
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пересечение и есть решение
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х∈ [1.5 ;7]