1) v(t) = S'(t) = (30t - 16t²)' = 30 - 32t;
v(t) = 0; 30 - 32t = 0; 32t = 30; t = 30/32 = 15/16 c - время торможения
2) S(15/16) = 30·(15/16) - 16(15/16)² = (15/16)(30 - 16(15/16)) = (15/16)(30 - 15) = (15/16)·15 = 225/16 = 14,0625 м - тормозной путь.