Решите пожалуйста даю 75 баллов

$5 - 2x = 3(10 + x) \\ 5 - 2x - 30 - 3x = 0 \\ - 25 - 5x = 0 \\ - 5x = 25 \\ x = - 5$

$\sqrt{x + 3} (5x - 6) = 0 \\ \sqrt{x + 3} = 0 \\ 5x - 6 = 0 \\ x + 3 = 0 \\ 5x = 6 \\ x = - 3 \\ x = \frac{6}{5} \\ - 3 + \frac{6}{5} = - 1.8$

$3 {x}^{2} - 13x + 12 = 0 \\ d = 169 - 4 \times 3 \times 12 = 169 - 144 = 25 \\ x = \frac{13 + 5}{6} = 3 \\ x2 = \frac{4}{3} \\ \frac{4}{3} \times 3 = 4$

4 - x \\ 3x - 6 - 4 + x > 0 \\ 4x - 10 > 0 \\ x > \frac{10}{4} " alt="3(x - 2) - 2 > 4 - x \\ 3x - 6 - 4 + x > 0 \\ 4x - 10 > 0 \\ x > \frac{10}{4} " align="absmiddle" class="latex-formula">