Решите уравнение; 1) 5х+1/6-х+3/4=3; 2) (4х-1) (3х-2)=(6х+1) (2х+3)-4х

Ответ:

1) x= $\frac{25}{48}$

2) x=- $\frac{1}{27}$

Объяснение:

1) 5x+ $\frac{1}{6}$ -x+ $\frac{3}{4}$ =3

4x+ $\frac{11}{12}$ =3

4x=3- $\frac{11}{12}$

4x= $\frac{25}{12}$

x= $\frac{25}{48}$

2) (4х-1) (3х-2)=(6х+1) (2х+3)-4х

12x²-8x-3x+2=12x²+18x+2x+3-4x

-8x-3x+2=18x+2x+3-4x

-11x+2=16x+3

-11x-16x=3-2

-27x=1

x=- $\frac{1}{27}$