1) ОДЗ :
x² - 5x + 6 > 0
(x - 2)(x - 3) > 0
+ - +
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2 3
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x ∈ (- ∞ ; 2) ∪ (3 ; + ∞)
-1\\\\0<\frac{1}{2}<1\\\\x^{2}-5x+6<2\\\\x^{2}-5x+4<0\\\\(x-1)(x-4)<0" alt="log_{\frac{1}{2} }(x^{2}-5x+6)>-1\\\\0<\frac{1}{2}<1\\\\x^{2}-5x+6<2\\\\x^{2}-5x+4<0\\\\(x-1)(x-4)<0" align="absmiddle" class="latex-formula">
+ - +
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1 4
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Ответ : x ∈ (1 ; 2) ∪ (3 ; 4)