1. 2x^6 - 13x^3 + 11 = 0 / x^3 = t
2t^2 - 13t + 11 = 0
D = b^2 - 4ac = 13^2 - 4 * 2 * 11 = 81
x1 = -b + !D / 2 = 13 + 9 / 2 = 11
x2 = -b - !D / 2 = 13 - 9 / 2 = 2
Ответ; 11, 2
2. 4(x^2 - x)^2 = 9(x^2 -x) + 2 = 0
4t^2 + 9t + 2 = 0
D = b^2 -4ac = 9^2 - 4 * 4 * 2 = 49
x1 = -b + !D / 2 = -9 + 7 / 2 = 1
x2 = -b + !D / 2 = -9 - 7 / 2 = -8
Если что ! - это кв. корень.