2cos^2x+корень из 3sin2x+1=0 [-п/2; 2п] ПОМОГИИИИИТЕ ПОЖААААЛУЙСТА
только 3
Корни, принадлежащие заданному отрезку:
спасииибо огромное
![x\in[-\frac\pi2;\;2\pi]:\\\\-\frac\pi2\leq\frac{2\pi}3+\pi k\leq2\pi\\\\-\frac\pi2-\frac{2\pi}3\leq\pi k\leq2\pi-\frac{2\pi}3\\\\-\frac{5\pi}6\leq\pi k\leq\frac{4\pi}3\\\\-\frac56\leq k\leq\frac43\\\\k\in\mathbb{Z}\Rightarrow k=0,\;1](https://tex.z-dn.net/?f=x%5Cin%5B-%5Cfrac%5Cpi2%3B%5C%3B2%5Cpi%5D%3A%5C%5C%5C%5C-%5Cfrac%5Cpi2%5Cleq%5Cfrac%7B2%5Cpi%7D3%2B%5Cpi%20k%5Cleq2%5Cpi%5C%5C%5C%5C-%5Cfrac%5Cpi2-%5Cfrac%7B2%5Cpi%7D3%5Cleq%5Cpi%20k%5Cleq2%5Cpi-%5Cfrac%7B2%5Cpi%7D3%5C%5C%5C%5C-%5Cfrac%7B5%5Cpi%7D6%5Cleq%5Cpi%20k%5Cleq%5Cfrac%7B4%5Cpi%7D3%5C%5C%5C%5C-%5Cfrac56%5Cleq%20k%5Cleq%5Cfrac43%5C%5C%5C%5Ck%5Cin%5Cmathbb%7BZ%7D%5CRightarrow%20k%3D0%2C%5C%3B1 "x\in[-\frac\pi2;\;2\pi]:\\\\-\frac\pi2\leq\frac{2\pi}3+\pi k\leq2\pi\\\\-\frac\pi2-\frac{2\pi}3\leq\pi k\leq2\pi-\frac{2\pi}3\\\\-\frac{5\pi}6\leq\pi k\leq\frac{4\pi}3\\\\-\frac56\leq k\leq\frac43\\\\k\in\mathbb{Z}\Rightarrow k=0,\;1")
