(2(x+y)-x+6=0, 3x-(x-y)=0

Question

(2(x+y)-x+6=0, 3x-(x-y)=0

Answer 1

Ответ:

2Х + 2Y - X = - 6  

X = - 6 - 2Y  

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3X - X + Y = 0  

2X + Y = 0  

2X = - Y  

- 12 - 4Y = - Y  

- Y + 4Y = - 12  

3Y = - 12  

Y = - 4  

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X = - 6 - 2 * ( - 4) = - 6 + 8 = 2

Пошаговое объяснение:

Comments

X=-6-2y

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-3y-12=0

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X=-6-2y

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2(-6-2)+y=0

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X=-6-2y

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y+4=0

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y=-4

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X+4=0

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X=2

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Y=4