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Решите задачу:

$\frac{5 {x}^{4} + 22 {x}^{3} + 8 {x}^{2} - x - 4 }{5 {x}^{3} + 2 {x}^{2} - 1} = \frac{5 {x}^{4} + 20 {x}^{3} + 2x {}^{3} + 8 {x}^{2} - x - 4 }{5 {x}^{3} + 2 {x}^{2} - 1} = \frac{(5 {x}^{4} + 20 {x}^{3}) + (2x {}^{3} + 8 {x}^{2}) + ( - x - 4) }{5 {x}^{3} + 2 {x}^{2} - 1} = \frac{5x {}^{3}(x + 4) + 2 {x}^{2} (x + 4) - (x + 4) }{5 {x}^{3} + 2 {x}^{2} - 1 } = \frac{(x + 4)(5 {x}^{3} + 2x {}^{2} - 1) }{5 {x}^{3} + 2 {x}^{2} - 1 } = x + 4 = 4 - 1.125 = 2.875$