Найти log7 28^1/3 если log2 7 = x

Question

Найти log7 28^1/3 если log2 7 = x

Answer 1

= 1/3*log7_28+1/3*(log7_7 +log7_4)=1/3*(1+log7_2^2)=1/3*(1+2log7_2)=1/3*(1+2x)=1/3+2x/3