{ 7y−2x=39; (3+x) 2 −(7−x) 2 =−16y. решите систему уравнения очень надо срочно прям...

Решите задачу:

$7y - 2x = 39 \\ 2(3 + x) - 2(7 - x) = - 16y \\ \\ 7y - 2x = 39 \\ 6 + 2x - 14 + 4x = - 16y \\ \\7y - 2x = 39 \\ 6x = 8 - 16y \\ \\ x = \frac{8 - 16y}{6} \\ 7y - 2( \frac{8 - 16y}{6} ) = 39 \\ \\ x = \frac{8 - 16y}{6} \\ 7y - 3(8 - 16y) = 39 \\ \\ x = \frac{8 - 16y}{6} \\ 7y - 24 + 48y = 39 \\ \\ x = \frac{8 - 16y}{6} \\ 55y = 63 \\ \\ x = \frac{8 - 16y}{6} \\ y = \frac{63}{55} = 1 \frac{8}{55} \\ \\ y = 1 \frac{8}{55} \\ x = \frac{8 - 16 \times \frac{63}{55} }{6} = - \frac{119}{165}$