-3x^2-x+4

Question

-3x^2-x+4<0 квадратное неравенство

Answer 1

0\\\\D=1+48=49\; \; ,\; \; x_1=-\frac{4}{3}\; \; ,\; \; x_2=1\\\\3(x+\frac{4}{3})(x-1)>0\\\\znaki:\; \; \; +++(-\frac{4}{3})---(1)+++\\\\x\in (-\infty ,-1\frac{1}{3})\cup (1,+\infty )" alt="-3x^2-x+4<0\\\\3x^2+x-4>0\\\\D=1+48=49\; \; ,\; \; x_1=-\frac{4}{3}\; \; ,\; \; x_2=1\\\\3(x+\frac{4}{3})(x-1)>0\\\\znaki:\; \; \; +++(-\frac{4}{3})---(1)+++\\\\x\in (-\infty ,-1\frac{1}{3})\cup (1,+\infty )" align="absmiddle" class="latex-formula">