1. 2cos2x=√2 2. cos(3x+пи/8)=5/2 3. 2cos^2x-1=0,5 4. cosx/3=1/2 при {-6пи;6пи) 5....

Question

1. 2cos2x=√2 2. cos(3x+пи/8)=5/2 3. 2cos^2x-1=0,5 4. cosx/3=1/2 при {-6пи;6пи) 5. (2cos4x-4)(2cosx+1)=0

Answer 1

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