\infty} \frac{n^2+2n+1}{n^2-1}=\\\\lim_{n->\infty} \frac{1+\frac{2}{n}+\frac{1}{n^2}}{1-\frac{1}{n^2}}=\\\\\frac{1+0+0}{1-0}=1" alt="lim_{n->\infty} \frac{n^2+2n+1}{n^2-1}=\\\\lim_{n->\infty} \frac{1+\frac{2}{n}+\frac{1}{n^2}}{1-\frac{1}{n^2}}=\\\\\frac{1+0+0}{1-0}=1" align="absmiddle" class="latex-formula">