Решить систему неравенствПж, срочно

Відповідь:

Покрокове пояснення^

a) $\left \{ {{6y\geq 42} \atop {4y+12\leq 0}} \right.$ $\left \{ {{y\geq 42:6} \atop {4y\leq 0-12}} \right.$ $\left \{ {{y\geq 7} \atop {4y\leq -12}} \right.$ $\left \{ {{y\geq 7} \atop {y\leq -12:4}} \right.$ $\left \{ {{y\geq 7} \atop {y\leq -3}} \right.$

(-∞;-3]∪[7;+∞)

б) 4} \atop {0.2x+1<6}} \right." alt="\left \{ {{0.3x>4} \atop {0.2x+1<6}} \right." align="absmiddle" class="latex-formula"> 4:0.3} \atop {0.2x<6-1}} \right." alt="\left \{ {{x>4:0.3} \atop {0.2x<6-1}} \right." align="absmiddle" class="latex-formula"> 13\frac{1}{3} } \atop {0.2x<5}} \right." alt="\left \{ {{x>13\frac{1}{3} } \atop {0.2x<5}} \right." align="absmiddle" class="latex-formula"> 13\frac{1}{3} } \atop {x<5:0.2}} \right." alt="\left \{ {{x>13\frac{1}{3} } \atop {x<5:0.2}} \right." align="absmiddle" class="latex-formula"> 13\frac{1}{3} } \atop {x<25}} \right." alt="\left \{ {{x>13\frac{1}{3} } \atop {x<25}} \right." align="absmiddle" class="latex-formula">

( $13\frac{1}{3}$ ;25)

в) 0}} \right." alt="\left \{ {{0.2x<3} \atop {\frac{1}{6} x>0}} \right." align="absmiddle" class="latex-formula"> 0:\frac{1}{6} }} \right." alt="\left \{ {{x<3:0.2} \atop { x>0:\frac{1}{6} }} \right." align="absmiddle" class="latex-formula"> 0}} \right." alt="\left \{ {{x<15} \atop { x>0}} \right." align="absmiddle" class="latex-formula">

(0;15)

г) 11} \atop {6x-18>0}} \right." alt="\left \{ {{1-5x>11} \atop {6x-18>0}} \right." align="absmiddle" class="latex-formula"> 11-1} \atop {6x>0+18}} \right." alt="\left \{ {{-5x>11-1} \atop {6x>0+18}} \right." align="absmiddle" class="latex-formula"> 10} \atop {6x>18}} \right." alt="\left \{ {{-5x>10} \atop {6x>18}} \right." align="absmiddle" class="latex-formula"> 10:(-5)} \atop {x>18:6}} \right." alt="\left \{ {{x>10:(-5)} \atop {x>18:6}} \right." align="absmiddle" class="latex-formula"> 3}} \right." alt="\left \{ {{x<-2} \atop {x>3}} \right." align="absmiddle" class="latex-formula">

(-∞;-2)∪(3;+∞)