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Решите задачу:

$tg45^\circ +\left (\dfrac{2\cdot sin30^\circ -\frac{cos45^\circ }{\sqrt2}}{\frac{sin60^\circ }{\sqrt3}+4\cdot cos60^\circ }\right)=1+\dfrac{2\cdot \frac{1}{2}-\frac{\sqrt2/2}{\sqrt2}}{\frac{\sqrt3/2}{\sqrt3}+4\cdot \frac{1}{2}}=\\\\\\=1+\dfrac{1-\frac{1}{2}}{\frac{1}{2}+2}=1+\dfrac{\frac{1}{2}}{\frac{5}{2}}=1+\dfrac{1}{5}=\dfrac{6}{5}=1,2$