6\\\\\\x\in (\, 6\, ;+\infty )" alt="\dfrac{\sqrt{x-6}}{x^2-36}\; \; \; \Rightarrow \quad \left\{\begin{array}{l}x-6\geq 0\\x^2-36\ne 0\end{array}\right\; \; \left\{\begin{array}{l}x\geq 6\\(x-6)(x+6)\ne 0\end{array}\right\\\\\\\left\{\begin{array}{l}x\geq 6\\x\ne -6\; ,\; x\ne 6\end{array}\right\qquad \Rightarrow \quad x>6\\\\\\x\in (\, 6\, ;+\infty )" align="absmiddle" class="latex-formula">